Check whether , x - 2 is a factor of the polynomial x3 - x2 - 4 by using factor theorem.
Answers
Answered by
25
Let,
x-2=0
x=2
Substitute value of x in the above equation
=(2)^3-(2)^2-4
=8-4-4
=0
x-2=0
x=2
Substitute value of x in the above equation
=(2)^3-(2)^2-4
=8-4-4
=0
anushkabhosale11:
thank you
Answered by
20
Explanation :
Factor theorem
If x - a is a factor of a function f ( x ) then x = a is a solution or zero of the function given .
Checking whether it holds true for f ( x )
x - 2 = 0
= > x = 2
Put this in f ( x )
x³ - x² - 4
= > 2³ - 2² - 4
= > 8 - 4 - 4
= > 8 - 8
= > 0
Hence f ( x ) = 0
This proves that x - 2 is a factor !
Hope it helps !
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