Question

Cison 5 COS A - 12 sin A = 0, find the value of
A COSA
2 cos A-sin A​

Answer 1

Given,

5 cos A - 12 sin A =0

5 cos A = 12 sin A

sin A/ cos A = 5/12

tan A =5/12

we know,

1+tan²A = sec²A

1 + (5/12)² =sec²A

1+25/144=sec²A

144+25/144=sec²A

169/144=sec²A

sec A= √169/144

sec A= 13/12

sec A=1/cos A

cos A=1/13/12

cos A=12/13

ŠüJäŁ ĐôÑgaŘè ✌

I HOPE THAT YOU GOT ANSWER PLZ FOLLOW ME PLZ MAKE ME BRAINLIST ANSWER ๏_๏