Question

CLARITY ACHIEVER
100 g of water at 30°C is heated. On heating its temperature rises to 40 °C. The amount of heat energy
supplied to the water is (specific heat of water is Ical glºc-)
a) 1000 cal
b) 8000 cal
c) 80 cal
d) 5400 cal​

Answer 1

Explanation:

$\huge\bf{\mid{\overline{\underline{Answer:-} \mid}}}$

$\huge\bold{Given:-} \\ \\ m = 100 g \\ T_1 = {30}^{\circ} C \\ T_2 = {40}^{\circ} C \\ c = 1- cal - {g}^{-1} - {^{\circ} C}^{-1} \\ \\ \huge\bold{To \: Find:-} \\ \\ Q (amount \: of \; heat) = ?$

$\Large\blue{Formula:-} \\ \\ Q = mc \Delta T \\ \\ \implies Q = m \times c \times \Delta T \\ \\ \implies Q = 100 \times 1 \times (40 - 30) \\ \\ \Huge\boxed{ \implies Q = 1000 cal}$