Question

Class 10 Coordinate Geometry

Answer 1

collinear points
(x1+x2+x3 )/3 , (y1+y2+y3)/3
if v consider only 2 points they have given
we will substitute in the formula and find out other if point is same then collinear
(7+(-2)+x3)/3=0
x3=-5
so the points r not collinear

Answer 2

S O L U T I O N :-

Let P(7,10) Q(-2,5) and R(3,-4)

Let➛x1=7

➛ x2=-2

➛ x3=3

➛ y1=10

➛ y2=5

➛ y3=-4

Now, by distance formula

⇢PQ=√[(x2-x1)²+(y2-y1)²]

⇢PQ=√[(-2-7)²+(5-10)²]

⇢PQ=√(-9)²+(-5)²

⇢PQ=√81+25

⇢PQ=√106

Again,

⇢QR=√[(x3-x2)²+(y3-y2)²]

⇢QR=√[(3-(-2))²+(-4-5)²]

⇢QR=√(5)²+(-9)²

⇢QR=√25+81

⇢QR=√106

Again,

⇢PR=√[(x1-x3)²+(y1-y3)²]

⇢PR=√[(7-3)²+(10+4)²]

⇢PR=√(4)²+(14)²

⇢PR=√16+196

⇢PR=√212=2√53

Now, PQ+QR=√106+√106=2√106

Here the sum of two sides is not equal to the third sides

Therefore, these points are not collinear .