class 11 ncert chemistry unit 5 ques. 5.7....i am getting the answer 8.314* 10^minus 2 instead of 8.314* 10^4... can u plz explain why is this so...??
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i don't know why u got that answer but i can solve it and u can re check your answer
Mass of CH 4= 3.2 g moles of CH 4
Moles of CH4 = 3.2/16 = 0.2
Mass of CO2 = 4.4 g moles of of CO
Moles of CO2 = 4.4/44
Total moles present in mixture = 0.2 +0.1 = 0.3
Given :
Volume of ask = 9 dm³ = 9 liter
Temperature = 273 + 27 = 300K
Now for pressure of mixture
Given formula :
P x V = nRT
P = (nRT)/V
P = (0.3 x 0.0821 x 300 )/9
P= 0.821 Latm
P= 8.314 x 10↑4 Pa
Mass of CH 4= 3.2 g moles of CH 4
Moles of CH4 = 3.2/16 = 0.2
Mass of CO2 = 4.4 g moles of of CO
Moles of CO2 = 4.4/44
Total moles present in mixture = 0.2 +0.1 = 0.3
Given :
Volume of ask = 9 dm³ = 9 liter
Temperature = 273 + 27 = 300K
Now for pressure of mixture
Given formula :
P x V = nRT
P = (nRT)/V
P = (0.3 x 0.0821 x 300 )/9
P= 0.821 Latm
P= 8.314 x 10↑4 Pa
mansi0811:
the value of R is given 8.314J K inverse mol inverse in ncert
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