Question

CLASS 9 ( Number System)​

Answer 1

Take R.HS.

rationalise the denominator

=> $\dfrac{2 + \sqrt{3}} {2 - \sqrt{3} }$

=> $\dfrac{2 + \sqrt{3} \times 2 + \sqrt{3} }{2 - \sqrt{3} \times 2 + \sqrt{3} }$

$= > \dfrac{ {(2)}^{2} + {( \sqrt{3} )}^{2} + 2 \times ( \sqrt{3}) \times 2 }{ {(2)}^{2} - (\sqrt{3} )^{2} }$

$= > \dfrac{4 + 3 + 4 \sqrt{3} }{4 - 3}$

$= > 7 + 4 \sqrt{3}$

Now, Compare R.H.S to L.H.S

a = 7

b = 4