Question

class 9 physics -
a body moves from one corner of an equilateral triangle of side 10 cm to the same corner along the sides. find the distance and displacement of the body​

Answer 1

Explanation:

Obviously, anything entering or leaving the body must cross at least one layer of epithelium

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Answer 2

Answer:

Distance of the body is 30cm.

Displacement of the body is 0cm.

Explanation:

Given:

A body is moving from one corner of an equilateral traingle of side 10cm to the same corner along the sides.

To Find:

The distance travelled by the body = ?

The displacement of the body = ?

Formula to be used:

Distance = Sum of all sides of triangle.

Displacement = Final position - Initial position.

Solution:

We know that,

A side of one side of traingle is given = 10cm.

The given triangle is an equilateral means all sides of the triangle are of same length = 10cm.

Now,

Distance of the body = ?

Let the triangle be ∆ABC.

Distance = Sum of all sides of the traingle.

Distance = AB + BC + AC

Distance = 10 + 10 + 10

Distance = 30cm.

$\therefore$ The distance of the body is 30cm.

Now,

Displacement of the body = ?

Displacement = Final position - Initial position.

Displacement = 0cm.

$\therefore$ Displacement of the body is 0cm.