CLASS WORK A voltmeter is connected across a variable resistance R which is in series with an ammeter and a cell. The cell is of emf E and internal resistance r. For a certain value of R, the ammeter reads 1 A and the voltmeter 3 V. When R is adjusted to another value, the ammeter reads 1.5 A and the voltmeter 2.5 V. i) Draw a circuit diagram of the set up described above; ii) Calculate the values of E and r, neglecting the resistance of the meters
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Answer:2OHM
Explanation:
ANSWER
Let E be the emf of the cell emf r be its internal resistance.
In the circuit the voltage equation can be written as,
E−I
r
−I
R
=0, where I=ammeter reading
but I
R
=v=voltmeter reading
⇒E−I
r
−V=0
⇒E=I
r
+V
From case i,
E=0.3r+0.9
From case ii,
E=0.25r+1
Equating both the equation,
0.3r+0.9=0.25r+1
⇒0.05r=0.1
⇒r=
0.05
0.1
=2ohms
Hence the internal resistance of the cell is 2 ohms.
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