Classroom is 11m long,8m wide, 5m high.find the cost of cementing its floor and walls at the rate of ₹20 per m
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Answered by
32
area of floor=11×8 sqm=88 sqm
so cost=Rs 20×88
area of 4 walls=2(l+b)×h=2(11+8)5=190
so cost of 4 walls=Rs 190 ×20
if they ask you the total cost then just add the 2 values whatever they are coming
so cost=Rs 20×88
area of 4 walls=2(l+b)×h=2(11+8)5=190
so cost of 4 walls=Rs 190 ×20
if they ask you the total cost then just add the 2 values whatever they are coming
Answered by
6
area of floor = 11×8=88 cm^2
cost of cementing its floor = 88×20
area of four walls = 2( 11+8)×5
=2×19×5=
cost = 19×2×5×20
=
if u need total cost then add it
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