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Step-by-step explanation:
multiply LHS by cosA /cosA to get
(sinA+1-cosA) / (sinA-1+cosA)
multiply again by cosA/cosA to get
(sinA.cosA+cosA-cos^2A) / cosA(sinA-1+cosA)
= ( cosA(1+sinA) - (1-sin^2A) ) / cosA(sinA-1+cosA)
= ( cosA(1+sinA) - (1+sinA)(1-sinA) ) / cosA(sinA-1+cosA)
= ( (1+sinA)(cosA-1+sinA) ) / cosA(sinA-1+cosA)
= (1+sinA)/cosA
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