Question

Coefficient of real expansion of mercury is 0.18×10−3/0C . If the density of mercury at 00C is 13.6gm/C.C , then is density at 473 K will be

Answer 1

Answer : 13.11g/C.C

Explanation :

ρ=ρ0(1+r0t)

=13.61+0.18×(2000C)

=13.61.036=13.11

Answer 2

Answer:

The density at 473 K is 13.12 gm/c³.

Explanation:

Given that,

Coefficient of real expansion of mercury $r_{0}=0.18\times10^{-3}\ /^{\circ}C$

Initial temperature = 0° C = 273 K

Density of mercury = 13.6 gm/c³

Final temperature = 473 K

We need to calculate the density at 473 K

Using formula of density

$\rho=\dfrac{\rho_{0}}{1+r_{0}\Delta T}$

Where, r₀ = Coefficient of real expansion

T = temperature

Put the value into the formula

$\rho=\dfrac{13.6}{(1+0.18\times10^{-3}\times(200))}$

$\rho=13.12\ gm/c^{3}$

Hence, The density at 473 K is 13.12 gm/c³.