coefficient of viscosity of terpentine oil flowing through a tube is found to depend on the pressure gradient ,velocity of the oil,and distance x from axis of tube (r square-x square)r is the radius of tube.by using method of dimentions derive expression for viscosity.
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11th
Physics
Units and Measurement
Dimensions and Dimensional Analysis
Turpentine oil is flowing t...
PHYSICS
Turpentine oil is flowing through a tube of length l and radius r. The pressure difference between the two ends of the tube is p. The viscosity of oil is given η=
4vl
p(r
2
−x
2
)
, where v is velocity of oil at a distance x from the axis of the tube. The dimensional formula of viscosity is
follow me
Dimensions of P=[ML
−1
T
−2
]
Dimentions of r=[L]
Dimentions of v=[LT
−1
]
Dimensions of I=[L]
η=
4vl
p(r
2
−x
2
)
=
[LT
−1
][L]
[ML
−1
T
−2
][L
2
]
=[ML
−1
T
−1
]
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