Coin tossed 6 timesprobability of getting 4 heads 5 heads 6 heads
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hey here is ur answer
p(e) =no. of favourable outcomes / total no. of outcomes
p(getting 4 heads) = 4/6
=2/3
p(getting 5 heads) =5/6
p(getting 6 heads) =6/6
=1
I hope this helps you
p(e) =no. of favourable outcomes / total no. of outcomes
p(getting 4 heads) = 4/6
=2/3
p(getting 5 heads) =5/6
p(getting 6 heads) =6/6
=1
I hope this helps you
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