Coins of same size are placed one above the other and a cylindrical block is formed . The volume of this block is 49.28cm³ . If the diameter of each coin be 2.8 cm and thickness 0.2 cm , then find the number of coins arranged in the block .
Answers
Answered by
95
Volume of cylinder = 49.28
πr^2h = 49.28
22/7 × 2.8/2 × 2.8/2 × h = 49.28
h = 8 cm
Thickness = 0.2 cm
Number of coins = Height/Thickness
= 80/2 = 40 coins
πr^2h = 49.28
22/7 × 2.8/2 × 2.8/2 × h = 49.28
h = 8 cm
Thickness = 0.2 cm
Number of coins = Height/Thickness
= 80/2 = 40 coins
akshatkaushik6p4cxut:
Thank You so much !! This question confused me !!
Answered by
30
Answer:
Step-by-step explanation:
Volume of the cyclinder is 49.28cm^3...
πr^2h= 49.28
22/7 * 1.4*1.4* h= 49.28
H=8cm....
No.of coins = height / thickness
8/0.2
80/2
=40 coins
We found out!!!
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