Comment upon the nature of roots for the equation x2 + 2√3x – 9 = 0
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Answer:
Real and distinct
Step-by-step explanation:
we can find nature of roots by finding the discriminant
Discriminant=b2-4ac (Here b2 means b square)
b=2√3,a=1,c=-9
(2√3)square-4×1×-9
4×3+4×9
12+36
=48
Nature of roots: Roots are real and distinct
I hope this answer may help you
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