Question

Compare the rates of radiation of metal sphere at 627° C and 327° C.​

Answer 1

Answer:

The rate of radiation of two sphere is in ratio 81 : 16

Explanation:

As we know that thermal radiation due to an object at given temperature T is given as

$\frac{dQ}{dt} = \sigma e A T^4$

now we know that

T = temperature in kelvin

now we need to compare two balls at different temperature

so we have

$\frac{\frac{dQ_1}{dt}}{\frac{dQ_2}{dt}} = \frac{T_1^4}{T_2^4}$

so we have

$\frac{\frac{dQ_1}{dt}}{\frac{dQ_2}{dt}} = \frac{(627 + 273)^4}{(327 + 273)^4}$\frac{\frac{dQ_1}{dt}}{\frac{dQ_2}{dt}} = \frac{900^4}{600^4}[/tex]

$\frac{\frac{dQ_1}{dt}}{\frac{dQ_2}{dt}} = \frac{81}{16}$

#Learn

Topic : Thermal Radiation

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