Question

Compare the resistance of two bulbs of 50 watt and 200 watt if they are at the same voltage

Answer 1

Explanation:

power, p=is square R= very square by R

so 200÷50 =4:1

Answer 2

The resistance of two bulbs of 50 watt and 200 watt is in the ratio of 4:1.

Explanation:

Given that,

Resistance of bulb 1 is 50 watts and the resistance of bulb 2 is 200 watts. The power of the bulb is given by :

$P=\dfrac{V^2}{R}$

V is voltage

Power of bulb 1,

$P_1=\dfrac{V^2}{R_1}$

Power of bulb 2,

$P_2=\dfrac{V^2}{R_2}$

So,

$\dfrac{P_1}{P_2}=\dfrac{R_2}{R_1}\\\\\dfrac{R_2}{R_1}=\dfrac{P_1}{P_2}\\\\\dfrac{R_2}{R_1}=\dfrac{200}{50}\\\\\dfrac{R_2}{R_1}=4\\\\\dfrac{R_1}{R_2}=\dfrac{1}{4}$

So, the resistance of two bulbs of 50 watt and 200 watt is in the ratio of 4:1.

Learn more,

Resistance

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