Question

Compare Vrms of the molecules of hydrogen and oxygen at 27 °C temperature and 1 atm pressure. (Molecular mass of hydrogen = 2 g/mol, Molecular mass of oxygen = 32 g/mol)

Answer 1

Explanation:

Here is your answer

At STP, Temperature = 273K and Pressure=1atm, diameter=3 Å =3x10-8 cm.

At STP, Temperature = 273K and Pressure=1atm, diameter=3 Å =3x10-8 cm.Actual volume by 1mole O2 gas at STP =22.4l = 22400cm3.

At STP, Temperature = 273K and Pressure=1atm, diameter=3 Å =3x10-8 cm.Actual volume by 1mole O2 gas at STP =22.4l = 22400cm3.Molecular volume of O2 = ((4/3) πr3) x NA

At STP, Temperature = 273K and Pressure=1atm, diameter=3 Å =3x10-8 cm.Actual volume by 1mole O2 gas at STP =22.4l = 22400cm3.Molecular volume of O2 = ((4/3) πr3) x NA= (4/3) x 3.14x (1.5x10-8)3x6.02x1023 =8.51cm3

At STP, Temperature = 273K and Pressure=1atm, diameter=3 Å =3x10-8 cm.Actual volume by 1mole O2 gas at STP =22.4l = 22400cm3.Molecular volume of O2 = ((4/3) πr3) x NA= (4/3) x 3.14x (1.5x10-8)3x6.02x1023 =8.51cm3Therefore, Ratio = (8.51/22400) = 3.8x10-4

Answer 2

Explanation:

At STP, Temperature = 273K and Pressure=1atm, diameter=3 Å =3x10-8 cm.

At STP, Temperature = 273K and Pressure=1atm, diameter=3 Å =3x10-8 cm.Actual volume by 1mole O2 gas at STP =22.4l = 22400cm3.

At STP, Temperature = 273K and Pressure=1atm, diameter=3 Å =3x10-8 cm.Actual volume by 1mole O2 gas at STP =22.4l = 22400cm3.Molecular volume of O2 = ((4/3) πr3) x NA

At STP, Temperature = 273K and Pressure=1atm, diameter=3 Å =3x10-8 cm.Actual volume by 1mole O2 gas at STP =22.4l = 22400cm3.Molecular volume of O2 = ((4/3) πr3) x NA= (4/3) x 3.14x (1.5x10-8)3x6.02x1023 =8.51cm3

At STP, Temperature = 273K and Pressure=1atm, diameter=3 Å =3x10-8 cm.Actual volume by 1mole O2 gas at STP =22.4l = 22400cm3.Molecular volume of O2 = ((4/3) πr3) x NA= (4/3) x 3.14x (1.5x10-8)3x6.02x1023 =8.51cm3Therefore, Ratio = (8.51/22400) = 3.8x10-4