Give the kinetic interpretation of temperature of gas.
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In science
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is not a lesson kinetic
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We have been given that,
Kinetic interpretation of temperature of gas
P V = \dfrac{1}{3} \times m \time c^{2} \\
According to the gas equation equation is P V = R T
m\time v^{2} =\dfra3\times R\times T\\\\
\dfrac{1}{2} m\time v^{2} =\dfrac{3}{2} R T
Kinetic energy =\dfrac{1}{2} m\time v^{2} =\dfrac{3}{2} R T\\
Kinetic energy = \dfrac{3}{2} R T =
\dfrac{1}{2} m v^{2} = kinetic energy per gram of mole per gram
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