Question

Complete the following chemical equation: $3X+3O_{2} \underrightarrow{\Delta}B_{2}O_{3}+3H_{2}O$

Answer 1

$3X+3O_2\rightarrow B_2O_3+3H_2O$

we need to find out what reacts with oxygen to give boron trioxide and 3 molecules of water. And we know Diborane reacts with oxygen to give boron trioxide and water.

We can also see the arrangement of molecules to find what lies in place of 3X

.

On the right-hand side, we have;

2 molecules of boron, 6 molecules of oxygen and 6 molecules of hydrogen

.

On left hand side we have;

6 molecules of oxygen, so remaining

                           $3X= B_2H_6 (DIBORANE)\\So\quad x = BF_3$

$B_2H_6+3O_2\xrightarrow {Heat} B_2O_3+3H_2O$

Answer 2

Explanation:

According to the law of conservation of mass, when a chemical reaction occurs, the mass of the products should be equal to the mass of the reactants. Therefore, the amount of the atoms in each element does not change in the chemical reaction. As a result, the chemical equation that shows the chemical reaction needs to be balanced. A balanced chemical equation occurs when the number of the atoms involved in the reactants side is equal to the number of atoms in the products side.

The given chemical reactions are balanced below:

(a) 2HNO

3

+Ca(OH)

2

⟶Ca(NO

3

)

2

+2H

2

O

(b)NaCl+AgNO

3

⟶AgCl+NaNO

3

(c)BaCl

2

+H

2

SO

4

⟶BaSO

4

+2HCl