Chemistry, asked by rockshrm2530, 11 months ago

Complete the following reaction
Cr2O7^2-+8H++3NO2^-

Answers

Answered by SAMEER36325
3

Cr2O72- + 3 NO2- + 8 H+ → 2 (Cr)3+ + 3 NO3- + 4 H2O

Answered by guruu99
0

Answer:

Cr2O7^2-+8H++3NO2^- → 2Cr^3+ + 7H2O+3NO3^-

Explanation:

This above reaction involves the oxidation of a dichromate ion (Cr2O7^2-) by nitrite ion (NO2^-) in an acidic medium. The oxidation of the dichromate ion is balanced by the reduction of nitrite ion. The oxidation process is followed by the release of H+ ions from the dichromate ion and the uptake of H+ ions by the nitrite ion. As a result, the dichromate ion is reduced to chromium (III) ions (Cr^3+). The nitrite ion is oxidized to nitrate ions (NO3^-). The overall reaction is considered to be exothermic, and water (H2O) is released as a product.

The reaction can be written as the following:

Cr2O7^2-+8H++3NO2^- → 2Cr^3+ + 7H2O+3NO3^-

The reaction involves an electrochemical mechanism. As the dichromate ion gains electrons and is reduced to chromium (III) ions, the nitrite ion loses electrons and is oxidized to nitrate ions. The reaction is an example of an oxidation-reduction reaction, where the oxidation of one species (dichromate ion) is balanced by the reduction of another species (nitrite ion).

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