Math, asked by tatyannamahmoup9nt5r, 1 year ago

Complete the table to determine if wavelength varies inversely with frequency. Let k be the product of wavelength and frequency.
Type of Radiation Wavelength (m) Frequency (1⁄sec) k
X–rays 1 × 10−10 3 × 1018 a
Radio waves 1 × 10−1 3 × 109 b
Green light 600 × 10−6 5 × 1011 c
UV rays 4 × 10−7 7.5 × 1014 d




Answers

Answered by ceecejefferson
24
The answers are
a= 3
b=3
c=3
d=3 
Answered by JackelineCasarez
3

Answer:

For the X–rays is a= 3\times 10^{8}

For the Radio waves is b= 3\times 10^{8}

For the Green light is c= 3\times 10^{8}.

For the UV rays is d= 3\times 10^{8}.

Step-by-step explanation:

As given

k be the product of wavelength and frequency.

i.e

k = wavelength × frequency

First part

X–rays

wavelength = 1\times 10^{-10}

frequency = 3\times 10^{18}

Put in above equation

k= 1\times 10^{-10}\times 3\times 10^{18}

Now by using the exponent property

x^{a}\times x^{b} = x^{a + b}

k= 3\times 10^{18-10}

k= 3\times 10^{8}

i.e

a= 3\times 10^{8}

Thus for the X–rays is a= 3\times 10^{8}

Second part

For Radio waves .

wavelength = 1\times 10^{-1}

frequency = 3\times 10^{9}

Put in above equation

k= 1\times 10^{-1}\times 3\times 10^{9}

Now by using the exponent property

x^{a}\times x^{b} = x^{a + b}

k= 3\times 10^{-1+9}

k= 3\times 10^{8}

i.e

b= 3\times 10^{8}

Thus for the Radio waves is b= 3\times 10^{8}.

Third part

For Green light

wavelength = 600\times 10^{-6}

frequency = 5\times 10^{11}

Put in above equation

k= 600\times 10^{-6}\times 5\times 10^{11}

Now by using the exponent property

x^{a}\times x^{b} = x^{a + b}

k= 3000\times 10^{-6+11}

k= 3\times 10^{5+3}

k= 3\times 10^{8}

i.e

c= 3\times 10^{8}

Thus for the Green light is c= 3\times 10^{8}.

Fourth part

For UV rays

wavelength = 4\times 10^{-7}

frequency = 7.5\times 10^{14}

Put in above equation

k= 4\times 10^{-7}\times 7.5\times 10^{14}

Now by using the exponent property

x^{a}\times x^{b} = x^{a + b}

k=30\times 10^{-7+14}

k= 30\times 10^{7}

k= 3\times 10^{7+1}

k= 3\times 10^{8}

i.e

d= 3\times 10^{8}

Thus for the UV rays is d= 3\times 10^{8}.

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