Question

completion of square method​

Answer 1

Answer:

Example: see that image.

Step-by-step explanation:

1. Divide all term by coefficient (the coefficient of xsquare).
2. Move the number term to the right side of the equation.
3. Complete the square on the left side of the equation and Balance this by adding the same value to the right side of the equation.

I hope you will understand

Answer 2

Answer:

Example: 2x²-7x +3=0

Step-by-step explanation:

=> 2x²-7=-3

On dividing both side of equation by 2 We Obtain

$= > x ^{2} - \frac{7}{2} x = - \frac{ 3}{ 2} \\ = > {x}^{2} - 2 \times x \times \frac{7}{2} = - \frac{3}{2}$

$On \: adding \:( { \frac{7}{4} })^{2} to\: both\: side \:of \:equation. \\ we obtain$

$= > ({x}^{2} ) - 2 \times x \times \frac{7}{4} + ({ \frac{7}{4} })^{2} = ( \frac{7}{4} ) \frac{ - 3}{2}$

$= > ( {x - \frac{7}{4} })^{2} = \frac{49}{16} - \frac{3}{6} \\ = > ( { x - \frac{7}{4} })^{2} = \frac{25}{16} \\ = > x = \frac{7}{4} - + \frac{5}{4} \\ = > x = \frac{7}{4} \: or \: x = \frac{7}{4} - \frac{5}{4} \\ = > x = \frac{12}{4} or \: x = \frac{2}{4} \\ = > x= 3 \: or \: \frac{1}{4}$