Question

compound interest on 16000 deposited for a period of 2years is 9000 findthe rate of interest​

Answer 1

Answer:

25%

Step-by-step explanation:

$using \: formula \\ {p(1 + \frac{r}{100}) }^{2} - p = interest \\ or \: 16000 {( \frac{100 + r}{100} ) }^{2} - 16000 = 9000 \\ or \: \frac{16000}{10000} \times {(100 + r)}^{2} = 25000 \\ or \: {(100 + r)}^{2} = \frac{250000}{16} \\ or \: 100 + r = \frac{500}{4} = 125 \\ or \: r = 125 - 100 = 25$

Answer 2

Answer:

Rate of ineterst = 25%

Step-by-step explanation: