Question

Compound Xe and F is found to have 53.5%. Xe.what is the oxidation number of Xe in the compound

Answer 1

Compound of Xe and F:
Percentage of Xe = 53.3%
Percentage of F = 100 - 53.3 = 46.7%

To find relative moles:

Xe = Percentage of compound/Atomic mass=53.3133 = 0.4
F = Percentage of compound/Atomic mass=46.719 = 2.45

NOW Mole ratio:
For Xe = 0.40.4= 1
For F = 2.450.4= 6

So the formula is XeF6.
Since F is present in -1 state therefore Xe exists in +6 state.
Hope you get answer of your question

Answer 2

Xe will have +6 oxidation state answer is as follows