Question

compute the heat generated while transferring 96000 coulomb of charge in 1 hour through a potential difference of 50 v.

Answer 1

Heat Produced (H) = 4800 KJ

Explanation:

★ Given :-

• Charge (Q) = 96,000 C
• Time taken (t) = 1 hour = 3600 s
• Potential Difference (v) = 50 V

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★ To Find :-

We have to find the heat generated

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★ Solution :-

As we have to find the heat generated. So, firstly we have to find the current.

Current(I) = Q/t

I = 96000/3600

I = 80/3 A

Now,

We have to find the resistance

Resistance (R) = V/I

R = 50/(80/3)

R = (50 * 3)/80

R = 150/80

R = 15/8 Ω

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Now,

Heat Produced (H) = I²Rt

H = (80/3)² * (15/8) * 3600

H = 4800000 J

H = 4800 KJ

Therefore, Heat produced is 4800 KJ.

Answer 2

Answer:

Given charge Q = 96000 coulomb.

time = 1hr = 60 * 60 = 3600s.

Potential difference {V} = 50v

According to formula: H= VIT -(i)

Also I = Q/T

∴I  = 96000/3600 =80/3= Ampere

putting value of I = 80/3 Ampere in (i)

H=50 X 80/3 X 60 X 60 = 4.8 X 10²×³joule

Heat is generated that is 4.8 X 10²×³ joule