Question

compute the number of ions present
in 5.85g of sodium chloride​

Answer 1

Answer:

MM of NaCl = 58.5

Moles = 5.85/58.5 = 0.1 mol

Answer 2

1 mole of NaCl = 58.5 g

x moles of NaCl = 5.85 g

By cross-multiplication , we get

5.85/58.5 = 0.1 moles

1 NaCl contains 1 Na+ ion and 1 Cl- ion, a total of 2 ions.

Thus 1 mole of NaCl contains 2*(Avogadro Number) of ions

=> 0.1 moles contains 0.2*(Avogadro Number) ions = 1.2 x 10^23 ions