Question

compute the value of 9x²+4y² if xy=6 and 3x+2y=12.

Answer 1

Answer:

$3x + 2y = 12 = > {(3x + 2y)}^{2} = {12}^{2} = > 9 {x}^{2} + 4 {y}^{2} + 12xy = 144$

$= > 9 {x}^{2} + 4 {y}^{2} + 12(6) = 144 = > 9 {x}^{2} + 4 {y}^{2} = 144 - 72 = 72$

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Answer 2

Answer:

72 is the answer

Step-by-step explanation:

xy=6

x=6/y

3(6/y) + 2y =12

18/y +2y = 12

18 + 2y^2

---------------- = 12

y

2y^2 -12y +18 = 0

y^2 -6y +9 = 0

y^2 -3y -3y +9 = 0

y(y-3) -3(y-3) =0

(y-3) (y-3) =0

y= 3

x=6/3 = 2

9(2)^2 + 4(3)^2

36+36

72 ans

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