Concentrated aqueous sulphuric acid is 98% h2so4 and has a density of 1.80 gm/L what is the molarity of solution? Plz don't send any link as I have checked them all Answrr of this ques. is 10M but I don't know the solution. Plz help...........
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To find Molarity, we need moles and volume in litres.
Moles of H2SO4: moles=mass/ molar mass...molar mass= (2+32+64)=98
mass of the H2SO4: since density is 1.8gmL that means 1800g in every liter.
and we know that this 98% H2SO4, hence its mass in 1liter would be (98/100 x 1800)=1764
therefore the moles= 1764/98 =18
Molarity of a solution= moles/volume(in litres).....the volume we used was a liter.
hence molarity will be 18moles/1litre= 18moles/litre
=18M
Moles of H2SO4: moles=mass/ molar mass...molar mass= (2+32+64)=98
mass of the H2SO4: since density is 1.8gmL that means 1800g in every liter.
and we know that this 98% H2SO4, hence its mass in 1liter would be (98/100 x 1800)=1764
therefore the moles= 1764/98 =18
Molarity of a solution= moles/volume(in litres).....the volume we used was a liter.
hence molarity will be 18moles/1litre= 18moles/litre
=18M
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