Question

conductivity of 0.12 m CuSO4 solution at 298 K is 1.8*10^-2. claculate its equivalent conductivity

Answer 1

Conductivity (κ) = 1.8 × 10⁻² S/cm
molarity (M) = 0.12M
n- factor of CuSO₄ = 2
Normality = n × molarity
Normality(N) = 2 × 0.12 = 0.24N

Equivalent conductivity ($\bold{\Lambda_{eq}}$) = κ × 1000/N
⇒equivalent conductivity = 1.8 × 10⁻² × 1000/0.24
= 7500 S.cm²/g/eq

Answer 2

Answer:

Equivalent conductivity is$7.5s \: {cm}^{ - 1} {equiv}^{ - 1}$