Question

CONGRUENCE OF TRIANGLES
A
In Fig 7.15, AB=AC and D is the mid-point of BC.
State the three pairs of equal parts in
1)ADB and ADC.
2) (Is ADB = ADC? Give reasons)
3) is B = C ? Why ?
​

Answer 1

Answer:

\angle B = \angle C.

Step-by-step explanation:

Here in  \Delta ADB and \Delta ADC.

i) Three pair of equal parts are:

AD = AD ( common side )  

BD = CD ( as d is the mid point of BC)

AB = AC (given in the question)

ii) Now,  

by SSS Congruency rule,

\Delta ADB\cong \Delta ADC

iii) As both triangles are congruent to each other we can compare them and say

\angle B = \angle C.

Answer 2

Answer:

Yes.

ADB = ADC. As both are 90degree

B=C can be proved by cpct

or

by proving the triangle as isosceles