Question

Consider the circuit shown where apb and aqb are semicircles

Answer 1

Answer:

Step-by-step explanation:

Magnetic field due to current through the semi−circular arc APB:

B1=μ04π2Ir (Perpendicular to the paper and inward)

Magnetic field due to current through the semi−circular arc AQB:

B2=μ04π2Ir (Perpendicular to the paper and outward)

As B1 and B2 are equal and opposite, the net magnetic field at the point C is equal to zero.

Answer 2

$\huge\underline\mathfrak\red{Answer}$

Consider the circuit shown in attachment where APB and AQB are semicircles. What will be the magnetic field at the centre C of the circular loop?

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Direction of magnetic field along APB is in clockwise direction and direction of magnetic field along AQB is in anti-clockwise direction. That is, magnetic fields at the point C will be equal and opposite. Hence, net magnetic field at C is zero.

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