Chemistry, asked by Anonymous, 8 months ago

consider the elements present in the box
(Ca,O,Cl,Na,Mg,C)
the total numbers of element(s) that form(s) divalent cation is
(a) 1
(b) 2
(c) 3
(d) 4​

Answers

Answered by soniyadahiya
1

Answer:

( b) 2…....…..............

Answered by honey270947
0
(B)2 I.e., magnesium and calcium
Because they lose electrons to obtain octet configuration
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