Consider the expression for x(t).
x(t)=[e²u(t)]* 8(t-4k)
It is given that x(t) = B * e ^ (- 2t) ; 0≤t<4. What is the value of B?
(a) 1-e6
(b). 1 1- e-8
(c) 1 -6 1-e
(d)1-e8
Answers
Answered by
1
Answer:
Correct option is B)
Givenxf(x)=x+∫1xf(t)dt
Differentiating both sides w.r.t. x, we get,
f(x)+xf′(x)=1+f(x)
⇒f(x)=log∣x∣+c
f(1)=1⇒f(x)=log∣x∣+1
⇒f(e−1)=0
Was this answer helpful?
Similar questions