Math, asked by gopal9885622798, 22 days ago

Consider the expression for x(t).

x(t)=[e²u(t)]* 8(t-4k)

It is given that x(t) = B * e ^ (- 2t) ; 0≤t<4. What is the value of B?

(a) 1-e6

(b). 1 1- e-8

(c) 1 -6 1-e

(d)1-e8​

Answers

Answered by vijayalakshmishobith
1

Answer:

Correct option is B)

Givenxf(x)=x+∫1xf(t)dt

Differentiating both sides w.r.t. x, we get,

f(x)+xf′(x)=1+f(x)

⇒f(x)=log∣x∣+c

f(1)=1⇒f(x)=log∣x∣+1

⇒f(e−1)=0

Was this answer helpful?

Similar questions