Question

Consider the following reversible chemical reactions:
A₂ (g) + B₂ (g) ⇄ᵏ¹ 2 AB (g) ....... (1)
6 AB (g) ⇄ᵏ² 3 A₂ (g) + 3B₂ (g) ....... (2)
The relation between K₁ and K₂ is
(A) K₁K₂ = 1/3
(B) K₂ = (K₁)³
(C) K₂ = (K₁)⁻³
(D) K₁K₂ = 3

Answer 1

Answer:

c. will be correct answers

Explanation:

reverse the second equation by deviding 3 .

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