Question

consider the ground state of Cr atom ( Z=24). the number of electrons with the azimuthal quantum number,l= 1 and 2 are , respectively options are 12 and 4, 12 and 5 , 16 and 4 ,16and 5

Answer 1

Answer:electrons in l=1 : 12

Electrons in l=2 : 5

Explanation:this is because :

For l = 0 1 2 3 4 5 ..........

Notation = s p d f g h ..........

Answer 2

The number of electrons with the azimuthal quantum number,l= 1 and 2 are 12 and 5.

• The ground state of the electronic configuration of Cr is as follows-
• ${1s}^{2} {2s}^{2} {2p}^{6} {3s}^{2} {3p}^{6} {4s}^{1} {3d}^{5}$
• l is called azimuthal quantum number. For l=1 the orbital is p and for l=2 the orbital is d.
• The total p orbital is 2p and 3p and the d orbital is 3d.
• Thus, the electron in the p orbital is 6+6=12.
• The number of electrons in the d orbital is 5.