Question

Consider the junction diode as ideal. The value of current flowing through AB is:(a) 0 A(b) 10⁻² A(c) 10⁻¹ A(d) 10⁻³ A

Answer 1

I think it will be zero because, we know that

I = V/R

So here as potential difference is connected in series so V = 0

Hence, 0 / 1 kilo ohm will be 0

Answer 2

Explanation:

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