Question

In the given figure, a diode D is connected to an external resistance R = 100 Ω and an e.m.f. of 3.5 V. If the barrier potential developed across the diode is 0.5 V, the current inthe circuit will be:(a) 40 mA(b) 20 mA(c) 35 mA(d) 30 mA

Answer 1

The answer will be current,

I = V/R

So 3.5 + 0.5 / 100 = 40 mA

Answer 2

Answer:

d) 30 mA

Explanation:

External Resistance = R = 100Ω (Given)

e.m.f. of the diode = 3.5V (Given)

Barrier potential developed across the diode = 0.5 V (Given)

Thus, the potential difference across the resistance R will be -

V = 3.5 - 0.5 = 3V

Thus, by the ohm's law, the current in the circuit is -

I = V/R

I = 3V/ 100Ω

I = 3 × 10²A

I = 3 × 10³A

I = 30mA

Thus, the current inthe circuit will be 30 mA.