Consider the number 4n², where n is a natural number. Check whether there is any value of n for which 4n ends with the zero.
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Answered by
5
Answer:
no, any value of n can never end with zero
Step-by-step explanation:
proof: 4=2*2
therefore 4n=2*2
but any number ends with zero has a factors of 2 and 5
here it is 2*2
hence for any value of power n it does not end with zero
hence proved
hope it helps
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vishwaram:
fine
Answered by
2
Step-by-step explanation:
→ No, 4ⁿ can never end with the digit 0 for any natural number n .
→ If 4ⁿ ends with 0 then it must have 5 as a factor .
But, 4ⁿ = ( 2² )ⁿ = 2²ⁿ .
→ It shows that 2 is the only prime factor of 4ⁿ .
Also, we know from the fundamental theorem of airthematic that the prime factorisation of each number is unique .
So, 5 is not a factor of 4ⁿ .
Hence, 4ⁿ can never end with the digit 0 .
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