Question

Consider the point a(1,0), b(4,0), and c(1,4). Then the triangle abc is a

Answer 1

Answer:

ΔABC is a right angle triangle

Step-by-step explanation:

A(1,0),B(4,0),C(1,4)

AB=√(4-1)³+0=3

BC=√(4-1)²+(0-4)²=√9+16

=√25=5

CA=√(1-1)²+(4-0)²

CA=√16=4

SO AB=3,BC=5,CA=4

AB²+CA²=9+16=25

and BC²=5²=25

AB²+CA²=BC²

hence ΔABC is a right angle triangle