consider the polynomial p(x)=4x square +5x+3 and find the zeroes
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(i) p(x) = 4x2 – 5x + 3
⇒ p(0) = 4(0)2 – 5(0) + 3
⇒ p(0) = 0– 0 + 3
⇒ p(0) = 3
(ii) p(x) = 4x2 – 5x + 3
⇒ p(-1) = 4(-1)2 – 5(-1) + 3
⇒ p(-1) = 4 × 1– (-5) + 3
⇒ p(-1) = 4 +5 + 3
⇒ p(-1) = 12
(iii) p(x) = 4x2 – 5x + 3
⇒ p(2) = 4(2)2 – 5(2) + 3
⇒ p(2) = 4 × 4– 10 + 3
⇒ p(2) = 16– 10 + 3
⇒ p(2) = 9
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