Construct a ∆abc in which ab=AC=5.6cm and a=120°. Draw ad!BC
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Step-by-step explanation:
Steps of Construction: Step 1: Draw a line segment BC = 4.5 cm. Step 2: At the point B, draw ∠XBC = 45°. Step 3: Draw an arc which intersects XB at point D form point B and with radius 5.6 cm Step 4: Join DC. Step 5: Draw a perpendicular bisector of DC which intersects DB at A. Step 6: Join AC. Hence, △ABC is the required triangle. Read more on Sarthaks.com - https://www.sarthaks.com/616874/construct-a-abc-in-which-ab-ac-5-6-cm-bc-4-5-cm-and-b-45
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