construct a parallelogram EFGH,in which EF=4.4 cm,HE=5.6 cm,AND angle HEF=105 degree.
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1) First draw EF=4.4 cm.
2) Then draw 105° angle at E.
3) Extend the angle line and cut it 5.6cm with the help of compass by keeping it at point E.
6) Name the point H.
7) From the point H draw an arc of 4.4 cm and from point F draw an arc of 5.6 cm .
8) At one point these 2 arcs will intersect, name that point G.
9) Join EG and HG the \\gm EFGH is formed.
I think that my answer will help u alot...
2) Then draw 105° angle at E.
3) Extend the angle line and cut it 5.6cm with the help of compass by keeping it at point E.
6) Name the point H.
7) From the point H draw an arc of 4.4 cm and from point F draw an arc of 5.6 cm .
8) At one point these 2 arcs will intersect, name that point G.
9) Join EG and HG the \\gm EFGH is formed.
I think that my answer will help u alot...
viduola:
i want a diagram
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