Construct a rectangle whose one diagonal is 6.8cm and an angle between two diagonal is 105°
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Step-by-step explanation:
Let the rectangle be ABCD, where AC=BD=6.8cm and O is point of intersection of diagonals
- Draw AC=6.8cm
- Mark a point O on AC such that AO=CO=3.4cm i.e at midpoint of AC
- From O draw angle 105° and extend it on both sides of AC
- Measure 3.4cm on the compass and cut the line drawn in step 3 from O
- Mark the points as B and D respectively
- Join AB, BC, CD and DA
Hence, ABCD is the required quadrilateral.
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