Math, asked by fjkhan1999, 3 months ago

Construct a right triangle with base 4.5 cm and the perimeter
11.7 cm

Answers

Answered by aggarwalyash2000
0

Answer:

AB = 4.5 cm

BC = 3.6 cm

AC = 3.6 cm

Step-by-step explanation:

given data

base = 4.5 cm

perimeter = 11.7 cm

solution

first we draw a line AB of length = 4.5 cm

and we have given perimeter = 11.7 cm

so we consider triangle is ABC

so perimeter is sum of all three side

perimeter = AB + BC+ AC .............1

11.7 cm = 4.5 + BC+ AC

BC+ AC = 7.2 cm

we take BC = AC

so BC = AC = \frac{7.2}{2}

2

7.2

= 3.6 cm

now we draw a arc from point A and B of 33.6

then then join the arc where it cut each other at point C

so as it is triangle

Hope it will be helpfull!! :D

Answered by manojkbbm11
0

Answer:

First draw a base of 4.5cm and then in ruler measure 11.7cm and draw a arc .Then join the two ends of the base to the arc .Triangle is formed.

Step-by-step explanation:

or AB = 4.5 cm

BC = 3.6 cm

AC = 3.6 cm

given data

base = 4.5 cm

perimeter = 11.7 cm

solution

first we draw a line AB of length = 4.5 cm

and we have given perimeter = 11.7 cm

so we consider triangle is ABC

so perimeter is sum of all three side

perimeter = AB + BC+ AC .............1

11.7 cm = 4.5 + BC+ AC

BC+ AC = 7.2 cm

we take BC = AC

so BC = AC = \frac{7.2}{2}

2

7.2

= 3.6 cm

now we draw a arc from point A and B of 33.6

then then join the arc where it cut each other at point C

so as it is triangle.

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