Construct a trapezium ABCD with AB || CD where AB = 6 cm, CD=4 cm,angle A = 70°,
angle ABD = 30°.
Answers
Step-by-step explanation:
Given:
AB
is parallel to
DC
, AB = 10 cm, BC = 5 cm, AC = 8 cm and CD = 6 cm.
Steps for construction:
Step 1 : Draw a rough diagram and mark the given measurements.
Step 2 : Draw a line segment AB = 10 cm.
Step 3 : With A and B as centres draw arcs of radii 8 cm and 5 cm respectively and let them cut at C.
Step 4 : Join
AC
and
BC
.
Step 5 : Draw
CX
parallel to
BA
.
Step 6 : With C as centre and radius 6 cm draw an arc cutting
CX
at D.
Step 7 : Join
AD
. ABCD is the required trapezium.
Step 8 : From C draw
CE
⊥
AB
and measure the length of CE. CE = h = 4 cm. AB = a = 10 cm, DC = b = 6 cm.
Calculation of area:
In the trapezium ABCD, a = 10 cm, b = 6 cm and h = 4 cm.
Area of the trapezium ABCD =
2
1
h(a+b)
=
2
1
(4)(10+6)
=
2
1
× 4 × 16
=32cm
2
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