construct a triangle ABC and divide segment BC in equal 5 parts
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Answer:
Given- ABCD is a parallelogram with BD as diagonal.
∠ABC=60
O
ΔBD
′
C
′
has been drawn similar to ΔBDC by a scale factor
3
4
which is greater than 1 i.e D
′
lies on extended BD and C
′
lies on extended BC
To determine- whether A
′
BC
′
D
′
is a parallelogram or not.
Solution-
ABCD is a parallelogram. i.e AB∥DC ....(i)
Now ΔBDC and ΔBD
′
C
′
ared similar (by construction)
∴∠BDC=∠BD
′
C
′
But they are corresponding angles.
∴DC∥D
′
C
′
⇒D
′
C
′
∥AB or A
′
B, since a
′
lies on extended BA .....(from (i)).
A
′
D
′
∥BC
′
......(by construction)........(iii)
So, from (ii) and (iii),
A
′
BC
′
D
′
is a parallelogram.
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