Question

Construct a triangle ABC in which BC = 5cm, angle B =60⁰ and AC + AB = 7.5 cm

Answer 1

Given : In Δ ABC , BC = 5am , AC + AB = 7.5cm and ∠ B = 60  

∘

 

To construct : Δ ABC

Steps of construction :  

1. Draw a ray BX and cut off a line segment BC = 5cm from it.

2. At B , construct ∠ XBY  = 60  

∘

 .

3. With B as center and radius = 7.5cm , draw an arc at meet BY at D.  

4. Join CD.  

5. Draw the perpendicular bisector of CD, by marking arc of length more than half of CD from both points C and D on both sides of it.

this line will be intersecting BD at A .  

6. Join AC . Then , ABC is the required triangle .

Answer 2

Step-by-step explanation:

Given, in ΔABC, BC=5 cm, ∠B=60° and AC + AB=7.5 cm. To construct the triangle ABC use the following steps.

Draw the base BC = 5 cm.

At the point B make an ∠XBC = 60°.

Cut a line segment BD equal to AB + AC = 7.5 cm from the ray BX.

Join DC.

Make an ∠DCY = ∠BDC.

Let CY intersect BX at A.

Then, ΔABC is the required triangle

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