Construct a triangle ABC in which three sides are in the ratio 1:3:5 and its perimeter is 13.5 c.m.
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solution:
Let the common multiple of the ratio be X
therefore the the three sides of the triangle ABC are 1x , 3x and 5x cm respectively
perimeter of the triangle=13.5 cm
perimeter = A+B+C
13.5= 1x+3x+5x
13.5 = 9x
therefore x=13.5 ÷9
x= 1.5 cm
therefore
1x=1×1.5=1.5
3x=3×1.5=4.5
5x=5×1.5=7.5
therefore
A=1.5cm
B=4.5cm
C=7.5cm
Now construct triangle ABC with base 7.5cm
Let the common multiple of the ratio be X
therefore the the three sides of the triangle ABC are 1x , 3x and 5x cm respectively
perimeter of the triangle=13.5 cm
perimeter = A+B+C
13.5= 1x+3x+5x
13.5 = 9x
therefore x=13.5 ÷9
x= 1.5 cm
therefore
1x=1×1.5=1.5
3x=3×1.5=4.5
5x=5×1.5=7.5
therefore
A=1.5cm
B=4.5cm
C=7.5cm
Now construct triangle ABC with base 7.5cm
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