construct a triangle abc whose perimeter is 10 cm and angle b is 30 degree and angle c is 60
Answers
Answered by
37
Well that's an easy one.
First draw a line segment XY=10 cm.
With X as centre draw a angle equal to half of 30 =15 and with Y as centre draw an angle =30
Which intersect previous ray at A. draw perpendicular bisected of both the rays which intersect XY at B and C respectively. Join A, B, C.
ABC is required triangle.
Hope this helps you...
First draw a line segment XY=10 cm.
With X as centre draw a angle equal to half of 30 =15 and with Y as centre draw an angle =30
Which intersect previous ray at A. draw perpendicular bisected of both the rays which intersect XY at B and C respectively. Join A, B, C.
ABC is required triangle.
Hope this helps you...
Answered by
8
Answer:
Step-by-step explanation:
Similar questions